3(2c+1)=2(4c-1)

Solution for 3(2c+1)=2(4c-1) equation:

Simplifying
3(2c + 1) = 2(4c + -1)

Reorder the terms:
3(1 + 2c) = 2(4c + -1)
(1 * 3 + 2c * 3) = 2(4c + -1)
(3 + 6c) = 2(4c + -1)

Reorder the terms:
3 + 6c = 2(-1 + 4c)
3 + 6c = (-1 * 2 + 4c * 2)
3 + 6c = (-2 + 8c)

Solving
3 + 6c = -2 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
3 + 6c + -8c = -2 + 8c + -8c

Combine like terms: 6c + -8c = -2c
3 + -2c = -2 + 8c + -8c

Combine like terms: 8c + -8c = 0
3 + -2c = -2 + 0
3 + -2c = -2

Add '-3' to each side of the equation.
3 + -3 + -2c = -2 + -3

Combine like terms: 3 + -3 = 0
0 + -2c = -2 + -3
-2c = -2 + -3

Combine like terms: -2 + -3 = -5
-2c = -5

Divide each side by '-2'.
c = 2.5

Simplifying
c = 2.5