3(2c+2)=5(3c-2)-5

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Solution for 3(2c+2)=5(3c-2)-5 equation:



3(2c+2)=5(3c-2)-5
We move all terms to the left:
3(2c+2)-(5(3c-2)-5)=0
We multiply parentheses
6c-(5(3c-2)-5)+6=0
We calculate terms in parentheses: -(5(3c-2)-5), so:
5(3c-2)-5
We multiply parentheses
15c-10-5
We add all the numbers together, and all the variables
15c-15
Back to the equation:
-(15c-15)
We get rid of parentheses
6c-15c+15+6=0
We add all the numbers together, and all the variables
-9c+21=0
We move all terms containing c to the left, all other terms to the right
-9c=-21
c=-21/-9
c=2+1/3

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