3(2c+3)=15

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Solution for 3(2c+3)=15 equation: 



3(2c+3)=15

We move all terms to the left:

3(2c+3)-(15)=0

We multiply parentheses

6c+9-15=0

We add all the numbers together, and all the variables

6c-6=0

We move all terms containing c to the left, all other terms to the right

6c=6

c=6/6

c=1

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