3(2c+4)=15

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Solution for 3(2c+4)=15 equation: 



3(2c+4)=15

We move all terms to the left:

3(2c+4)-(15)=0

We multiply parentheses

6c+12-15=0

We add all the numbers together, and all the variables

6c-3=0

We move all terms containing c to the left, all other terms to the right

6c=3

c=3/6

c=1/2

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