3(2c+4)=2(4c-1)

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Solution for 3(2c+4)=2(4c-1) equation: 



3(2c+4)=2(4c-1)

We move all terms to the left:

3(2c+4)-(2(4c-1))=0

We multiply parentheses

6c-(2(4c-1))+12=0



We calculate terms in parentheses: -(2(4c-1)), so:

2(4c-1)

We multiply parentheses

8c-2

Back to the equation:

-(8c-2)



We get rid of parentheses

6c-8c+2+12=0

We add all the numbers together, and all the variables

-2c+14=0

We move all terms containing c to the left, all other terms to the right

-2c=-14

c=-14/-2

c=+7

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