3(2c+4)=2(4c-1)

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Solution for 3(2c+4)=2(4c-1) equation:



3(2c+4)=2(4c-1)
We move all terms to the left:
3(2c+4)-(2(4c-1))=0
We multiply parentheses
6c-(2(4c-1))+12=0
We calculate terms in parentheses: -(2(4c-1)), so:
2(4c-1)
We multiply parentheses
8c-2
Back to the equation:
-(8c-2)
We get rid of parentheses
6c-8c+2+12=0
We add all the numbers together, and all the variables
-2c+14=0
We move all terms containing c to the left, all other terms to the right
-2c=-14
c=-14/-2
c=+7

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