3(2c+4)=7(c+1)

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Solution for 3(2c+4)=7(c+1) equation:


Simplifying
3(2c + 4) = 7(c + 1)

Reorder the terms:
3(4 + 2c) = 7(c + 1)
(4 * 3 + 2c * 3) = 7(c + 1)
(12 + 6c) = 7(c + 1)

Reorder the terms:
12 + 6c = 7(1 + c)
12 + 6c = (1 * 7 + c * 7)
12 + 6c = (7 + 7c)

Solving
12 + 6c = 7 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
12 + 6c + -7c = 7 + 7c + -7c

Combine like terms: 6c + -7c = -1c
12 + -1c = 7 + 7c + -7c

Combine like terms: 7c + -7c = 0
12 + -1c = 7 + 0
12 + -1c = 7

Add '-12' to each side of the equation.
12 + -12 + -1c = 7 + -12

Combine like terms: 12 + -12 = 0
0 + -1c = 7 + -12
-1c = 7 + -12

Combine like terms: 7 + -12 = -5
-1c = -5

Divide each side by '-1'.
c = 5

Simplifying
c = 5

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