3(2c+5)=(2c+17)

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Solution for 3(2c+5)=(2c+17) equation: 



3(2c+5)=(2c+17)

We move all terms to the left:

3(2c+5)-((2c+17))=0

We multiply parentheses

6c-((2c+17))+15=0



We calculate terms in parentheses: -((2c+17)), so:

(2c+17)

We get rid of parentheses

2c+17

Back to the equation:

-(2c+17)



We get rid of parentheses

6c-2c-17+15=0

We add all the numbers together, and all the variables

4c-2=0

We move all terms containing c to the left, all other terms to the right

4c=2

c=2/4

c=1/2

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