3(2c+5)=4(c+3)

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Solution for 3(2c+5)=4(c+3) equation: 



3(2c+5)=4(c+3)

We move all terms to the left:

3(2c+5)-(4(c+3))=0

We multiply parentheses

6c-(4(c+3))+15=0



We calculate terms in parentheses: -(4(c+3)), so:

4(c+3)

We multiply parentheses

4c+12

Back to the equation:

-(4c+12)



We get rid of parentheses

6c-4c-12+15=0

We add all the numbers together, and all the variables

2c+3=0

We move all terms containing c to the left, all other terms to the right

2c=-3

c=-3/2

c=-1+1/2

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