3(2c+6)=2(c-3)

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Solution for 3(2c+6)=2(c-3) equation: 



3(2c+6)=2(c-3)

We move all terms to the left:

3(2c+6)-(2(c-3))=0

We multiply parentheses

6c-(2(c-3))+18=0



We calculate terms in parentheses: -(2(c-3)), so:

2(c-3)

We multiply parentheses

2c-6

Back to the equation:

-(2c-6)



We get rid of parentheses

6c-2c+6+18=0

We add all the numbers together, and all the variables

4c+24=0

We move all terms containing c to the left, all other terms to the right

4c=-24

c=-24/4

c=-6

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