3(2c-1)-4=3c+8

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Solution for 3(2c-1)-4=3c+8 equation:


Simplifying
3(2c + -1) + -4 = 3c + 8

Reorder the terms:
3(-1 + 2c) + -4 = 3c + 8
(-1 * 3 + 2c * 3) + -4 = 3c + 8
(-3 + 6c) + -4 = 3c + 8

Reorder the terms:
-3 + -4 + 6c = 3c + 8

Combine like terms: -3 + -4 = -7
-7 + 6c = 3c + 8

Reorder the terms:
-7 + 6c = 8 + 3c

Solving
-7 + 6c = 8 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-7 + 6c + -3c = 8 + 3c + -3c

Combine like terms: 6c + -3c = 3c
-7 + 3c = 8 + 3c + -3c

Combine like terms: 3c + -3c = 0
-7 + 3c = 8 + 0
-7 + 3c = 8

Add '7' to each side of the equation.
-7 + 7 + 3c = 8 + 7

Combine like terms: -7 + 7 = 0
0 + 3c = 8 + 7
3c = 8 + 7

Combine like terms: 8 + 7 = 15
3c = 15

Divide each side by '3'.
c = 5

Simplifying
c = 5

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