3(2c-1)-5=4c+6

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Solution for 3(2c-1)-5=4c+6 equation:


Simplifying
3(2c + -1) + -5 = 4c + 6

Reorder the terms:
3(-1 + 2c) + -5 = 4c + 6
(-1 * 3 + 2c * 3) + -5 = 4c + 6
(-3 + 6c) + -5 = 4c + 6

Reorder the terms:
-3 + -5 + 6c = 4c + 6

Combine like terms: -3 + -5 = -8
-8 + 6c = 4c + 6

Reorder the terms:
-8 + 6c = 6 + 4c

Solving
-8 + 6c = 6 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-8 + 6c + -4c = 6 + 4c + -4c

Combine like terms: 6c + -4c = 2c
-8 + 2c = 6 + 4c + -4c

Combine like terms: 4c + -4c = 0
-8 + 2c = 6 + 0
-8 + 2c = 6

Add '8' to each side of the equation.
-8 + 8 + 2c = 6 + 8

Combine like terms: -8 + 8 = 0
0 + 2c = 6 + 8
2c = 6 + 8

Combine like terms: 6 + 8 = 14
2c = 14

Divide each side by '2'.
c = 7

Simplifying
c = 7

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