3(2c-1)-6=4c+7

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Solution for 3(2c-1)-6=4c+7 equation: 



3(2c-1)-6=4c+7

We move all terms to the left:

3(2c-1)-6-(4c+7)=0

We multiply parentheses

6c-(4c+7)-3-6=0

We get rid of parentheses

6c-4c-7-3-6=0

We add all the numbers together, and all the variables

2c-16=0

We move all terms containing c to the left, all other terms to the right

2c=16

c=16/2

c=8

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