3(2c-3)-1=-4(2c+1)+8

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Solution for 3(2c-3)-1=-4(2c+1)+8 equation: 


Simplifying
3(2c + -3) + -1 = -4(2c + 1) + 8

Reorder the terms:
3(-3 + 2c) + -1 = -4(2c + 1) + 8
(-3 * 3 + 2c * 3) + -1 = -4(2c + 1) + 8
(-9 + 6c) + -1 = -4(2c + 1) + 8

Reorder the terms:
-9 + -1 + 6c = -4(2c + 1) + 8

Combine like terms: -9 + -1 = -10
-10 + 6c = -4(2c + 1) + 8

Reorder the terms:
-10 + 6c = -4(1 + 2c) + 8
-10 + 6c = (1 * -4 + 2c * -4) + 8
-10 + 6c = (-4 + -8c) + 8

Reorder the terms:
-10 + 6c = -4 + 8 + -8c

Combine like terms: -4 + 8 = 4
-10 + 6c = 4 + -8c

Solving
-10 + 6c = 4 + -8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '8c' to each side of the equation.
-10 + 6c + 8c = 4 + -8c + 8c

Combine like terms: 6c + 8c = 14c
-10 + 14c = 4 + -8c + 8c

Combine like terms: -8c + 8c = 0
-10 + 14c = 4 + 0
-10 + 14c = 4

Add '10' to each side of the equation.
-10 + 10 + 14c = 4 + 10

Combine like terms: -10 + 10 = 0
0 + 14c = 4 + 10
14c = 4 + 10

Combine like terms: 4 + 10 = 14
14c = 14

Divide each side by '14'.
c = 1

Simplifying
c = 1

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