3(2c-4)=2(2c-2)

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Solution for 3(2c-4)=2(2c-2) equation:


Simplifying
3(2c + -4) = 2(2c + -2)

Reorder the terms:
3(-4 + 2c) = 2(2c + -2)
(-4 * 3 + 2c * 3) = 2(2c + -2)
(-12 + 6c) = 2(2c + -2)

Reorder the terms:
-12 + 6c = 2(-2 + 2c)
-12 + 6c = (-2 * 2 + 2c * 2)
-12 + 6c = (-4 + 4c)

Solving
-12 + 6c = -4 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-12 + 6c + -4c = -4 + 4c + -4c

Combine like terms: 6c + -4c = 2c
-12 + 2c = -4 + 4c + -4c

Combine like terms: 4c + -4c = 0
-12 + 2c = -4 + 0
-12 + 2c = -4

Add '12' to each side of the equation.
-12 + 12 + 2c = -4 + 12

Combine like terms: -12 + 12 = 0
0 + 2c = -4 + 12
2c = -4 + 12

Combine like terms: -4 + 12 = 8
2c = 8

Divide each side by '2'.
c = 4

Simplifying
c = 4

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