3(2c-5)+4=49

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Solution for 3(2c-5)+4=49 equation: 



3(2c-5)+4=49

We move all terms to the left:

3(2c-5)+4-(49)=0

We add all the numbers together, and all the variables

3(2c-5)-45=0

We multiply parentheses

6c-15-45=0

We add all the numbers together, and all the variables

6c-60=0

We move all terms containing c to the left, all other terms to the right

6c=60

c=60/6

c=10

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