3(2c-5)-4(2-c)=3(4c-5)

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Solution for 3(2c-5)-4(2-c)=3(4c-5) equation:


Simplifying
3(2c + -5) + -4(2 + -1c) = 3(4c + -5)

Reorder the terms:
3(-5 + 2c) + -4(2 + -1c) = 3(4c + -5)
(-5 * 3 + 2c * 3) + -4(2 + -1c) = 3(4c + -5)
(-15 + 6c) + -4(2 + -1c) = 3(4c + -5)
-15 + 6c + (2 * -4 + -1c * -4) = 3(4c + -5)
-15 + 6c + (-8 + 4c) = 3(4c + -5)

Reorder the terms:
-15 + -8 + 6c + 4c = 3(4c + -5)

Combine like terms: -15 + -8 = -23
-23 + 6c + 4c = 3(4c + -5)

Combine like terms: 6c + 4c = 10c
-23 + 10c = 3(4c + -5)

Reorder the terms:
-23 + 10c = 3(-5 + 4c)
-23 + 10c = (-5 * 3 + 4c * 3)
-23 + 10c = (-15 + 12c)

Solving
-23 + 10c = -15 + 12c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12c' to each side of the equation.
-23 + 10c + -12c = -15 + 12c + -12c

Combine like terms: 10c + -12c = -2c
-23 + -2c = -15 + 12c + -12c

Combine like terms: 12c + -12c = 0
-23 + -2c = -15 + 0
-23 + -2c = -15

Add '23' to each side of the equation.
-23 + 23 + -2c = -15 + 23

Combine like terms: -23 + 23 = 0
0 + -2c = -15 + 23
-2c = -15 + 23

Combine like terms: -15 + 23 = 8
-2c = 8

Divide each side by '-2'.
c = -4

Simplifying
c = -4

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