3(2c-5)=2(c-3)

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Solution for 3(2c-5)=2(c-3) equation: 



3(2c-5)=2(c-3)

We move all terms to the left:

3(2c-5)-(2(c-3))=0

We multiply parentheses

6c-(2(c-3))-15=0



We calculate terms in parentheses: -(2(c-3)), so:

2(c-3)

We multiply parentheses

2c-6

Back to the equation:

-(2c-6)



We get rid of parentheses

6c-2c+6-15=0

We add all the numbers together, and all the variables

4c-9=0

We move all terms containing c to the left, all other terms to the right

4c=9

c=9/4

c=2+1/4

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