3(2c-7)+4(3c+2)=61

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Solution for 3(2c-7)+4(3c+2)=61 equation: 



3(2c-7)+4(3c+2)=61

We move all terms to the left:

3(2c-7)+4(3c+2)-(61)=0

We multiply parentheses

6c+12c-21+8-61=0

We add all the numbers together, and all the variables

18c-74=0

We move all terms containing c to the left, all other terms to the right

18c=74

c=74/18

c=4+1/9

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