3(2c-d)-4(d-2c)=

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Solution for 3(2c-d)-4(d-2c)= equation:


Simplifying
3(2c + -1d) + -4(d + -2c) = 0
(2c * 3 + -1d * 3) + -4(d + -2c) = 0
(6c + -3d) + -4(d + -2c) = 0

Reorder the terms:
6c + -3d + -4(-2c + d) = 0
6c + -3d + (-2c * -4 + d * -4) = 0
6c + -3d + (8c + -4d) = 0

Reorder the terms:
6c + 8c + -3d + -4d = 0

Combine like terms: 6c + 8c = 14c
14c + -3d + -4d = 0

Combine like terms: -3d + -4d = -7d
14c + -7d = 0

Solving
14c + -7d = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '7d' to each side of the equation.
14c + -7d + 7d = 0 + 7d

Combine like terms: -7d + 7d = 0
14c + 0 = 0 + 7d
14c = 0 + 7d
Remove the zero:
14c = 7d

Divide each side by '14'.
c = 0.5d

Simplifying
c = 0.5d

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