3(2d+-8)=11d-18(d+-3)

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Solution for 3(2d+-8)=11d-18(d+-3) equation: 



3(2d+-8)=11d-18(d+-3)

We move all terms to the left:

3(2d+-8)-(11d-18(d+-3))=0

We add all the numbers together, and all the variables

3(2d-8)-(11d-18(d-3))=0

We multiply parentheses

6d-(11d-18(d-3))-24=0



We calculate terms in parentheses: -(11d-18(d-3)), so:

11d-18(d-3)

We multiply parentheses

11d-18d+54

We add all the numbers together, and all the variables

-7d+54

Back to the equation:

-(-7d+54)



We get rid of parentheses

6d+7d-54-24=0

We add all the numbers together, and all the variables

13d-78=0

We move all terms containing d to the left, all other terms to the right

13d=78

d=78/13

d=6

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