3(2d+1)=4d+19

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Solution for 3(2d+1)=4d+19 equation:


Simplifying
3(2d + 1) = 4d + 19

Reorder the terms:
3(1 + 2d) = 4d + 19
(1 * 3 + 2d * 3) = 4d + 19
(3 + 6d) = 4d + 19

Reorder the terms:
3 + 6d = 19 + 4d

Solving
3 + 6d = 19 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
3 + 6d + -4d = 19 + 4d + -4d

Combine like terms: 6d + -4d = 2d
3 + 2d = 19 + 4d + -4d

Combine like terms: 4d + -4d = 0
3 + 2d = 19 + 0
3 + 2d = 19

Add '-3' to each side of the equation.
3 + -3 + 2d = 19 + -3

Combine like terms: 3 + -3 = 0
0 + 2d = 19 + -3
2d = 19 + -3

Combine like terms: 19 + -3 = 16
2d = 16

Divide each side by '2'.
d = 8

Simplifying
d = 8

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