3(2d+4)+d=40

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Solution for 3(2d+4)+d=40 equation: 



3(2d+4)+d=40

We move all terms to the left:

3(2d+4)+d-(40)=0

We add all the numbers together, and all the variables

d+3(2d+4)-40=0

We multiply parentheses

d+6d+12-40=0

We add all the numbers together, and all the variables

7d-28=0

We move all terms containing d to the left, all other terms to the right

7d=28

d=28/7

d=4

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