3(2d-1)+5=4(d+1)

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Solution for 3(2d-1)+5=4(d+1) equation:


Simplifying
3(2d + -1) + 5 = 4(d + 1)

Reorder the terms:
3(-1 + 2d) + 5 = 4(d + 1)
(-1 * 3 + 2d * 3) + 5 = 4(d + 1)
(-3 + 6d) + 5 = 4(d + 1)

Reorder the terms:
-3 + 5 + 6d = 4(d + 1)

Combine like terms: -3 + 5 = 2
2 + 6d = 4(d + 1)

Reorder the terms:
2 + 6d = 4(1 + d)
2 + 6d = (1 * 4 + d * 4)
2 + 6d = (4 + 4d)

Solving
2 + 6d = 4 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
2 + 6d + -4d = 4 + 4d + -4d

Combine like terms: 6d + -4d = 2d
2 + 2d = 4 + 4d + -4d

Combine like terms: 4d + -4d = 0
2 + 2d = 4 + 0
2 + 2d = 4

Add '-2' to each side of the equation.
2 + -2 + 2d = 4 + -2

Combine like terms: 2 + -2 = 0
0 + 2d = 4 + -2
2d = 4 + -2

Combine like terms: 4 + -2 = 2
2d = 2

Divide each side by '2'.
d = 1

Simplifying
d = 1

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