3(2d-1)-2=4(d-1)+5

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Solution for 3(2d-1)-2=4(d-1)+5 equation: 



3(2d-1)-2=4(d-1)+5

We move all terms to the left:

3(2d-1)-2-(4(d-1)+5)=0

We multiply parentheses

6d-(4(d-1)+5)-3-2=0



We calculate terms in parentheses: -(4(d-1)+5), so:

4(d-1)+5

We multiply parentheses

4d-4+5

We add all the numbers together, and all the variables

4d+1

Back to the equation:

-(4d+1)



We add all the numbers together, and all the variables

6d-(4d+1)-5=0

We get rid of parentheses

6d-4d-1-5=0

We add all the numbers together, and all the variables

2d-6=0

We move all terms containing d to the left, all other terms to the right

2d=6

d=6/2

d=3

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