3(2d-1)-2=4(d-2)=5

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Solution for 3(2d-1)-2=4(d-2)=5 equation: 



3(2d-1)-2=4(d-2)=5

We move all terms to the left:

3(2d-1)-2-(4(d-2))=0

We multiply parentheses

6d-(4(d-2))-3-2=0



We calculate terms in parentheses: -(4(d-2)), so:

4(d-2)

We multiply parentheses

4d-8

Back to the equation:

-(4d-8)



We add all the numbers together, and all the variables

6d-(4d-8)-5=0

We get rid of parentheses

6d-4d+8-5=0

We add all the numbers together, and all the variables

2d+3=0

We move all terms containing d to the left, all other terms to the right

2d=-3

d=-3/2

d=-1+1/2

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