3(2d-1)-2d=4(d-2)+2

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Solution for 3(2d-1)-2d=4(d-2)+2 equation: 



3(2d-1)-2d=4(d-2)+2

We move all terms to the left:

3(2d-1)-2d-(4(d-2)+2)=0

We add all the numbers together, and all the variables

-2d+3(2d-1)-(4(d-2)+2)=0

We multiply parentheses

-2d+6d-(4(d-2)+2)-3=0



We calculate terms in parentheses: -(4(d-2)+2), so:

4(d-2)+2

We multiply parentheses

4d-8+2

We add all the numbers together, and all the variables

4d-6

Back to the equation:

-(4d-6)



We add all the numbers together, and all the variables

4d-(4d-6)-3=0

We get rid of parentheses

4d-4d+6-3=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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