3(2d-1)-2d=4(d-2)+5

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Solution for 3(2d-1)-2d=4(d-2)+5 equation: 


Simplifying
3(2d + -1) + -2d = 4(d + -2) + 5

Reorder the terms:
3(-1 + 2d) + -2d = 4(d + -2) + 5
(-1 * 3 + 2d * 3) + -2d = 4(d + -2) + 5
(-3 + 6d) + -2d = 4(d + -2) + 5

Combine like terms: 6d + -2d = 4d
-3 + 4d = 4(d + -2) + 5

Reorder the terms:
-3 + 4d = 4(-2 + d) + 5
-3 + 4d = (-2 * 4 + d * 4) + 5
-3 + 4d = (-8 + 4d) + 5

Reorder the terms:
-3 + 4d = -8 + 5 + 4d

Combine like terms: -8 + 5 = -3
-3 + 4d = -3 + 4d

Add '3' to each side of the equation.
-3 + 3 + 4d = -3 + 3 + 4d

Combine like terms: -3 + 3 = 0
0 + 4d = -3 + 3 + 4d
4d = -3 + 3 + 4d

Combine like terms: -3 + 3 = 0
4d = 0 + 4d
4d = 4d

Add '-4d' to each side of the equation.
4d + -4d = 4d + -4d

Combine like terms: 4d + -4d = 0
0 = 4d + -4d

Combine like terms: 4d + -4d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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