3(2d-1)-2d=4(d-4)+5

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Solution for 3(2d-1)-2d=4(d-4)+5 equation: 



3(2d-1)-2d=4(d-4)+5

We move all terms to the left:

3(2d-1)-2d-(4(d-4)+5)=0

We add all the numbers together, and all the variables

-2d+3(2d-1)-(4(d-4)+5)=0

We multiply parentheses

-2d+6d-(4(d-4)+5)-3=0



We calculate terms in parentheses: -(4(d-4)+5), so:

4(d-4)+5

We multiply parentheses

4d-16+5

We add all the numbers together, and all the variables

4d-11

Back to the equation:

-(4d-11)



We add all the numbers together, and all the variables

4d-(4d-11)-3=0

We get rid of parentheses

4d-4d+11-3=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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