3(2d-1)2d=4(d-2)+5

Solution for 3(2d-1)2d=4(d-2)+5 equation:

3(2d-1)2d=4(d-2)+5

We move all terms to the left:

3(2d-1)2d-(4(d-2)+5)=0

We multiply parentheses

12d^2-6d-(4(d-2)+5)=0


We calculate terms in parentheses: -(4(d-2)+5), so:

4(d-2)+5

We multiply parentheses

4d-8+5

We add all the numbers together, and all the variables

4d-3

Back to the equation:

-(4d-3)


We get rid of parentheses

12d^2-6d-4d+3=0

We add all the numbers together, and all the variables

12d^2-10d+3=0

a = 12; b = -10; c = +3;
Δ = b2-4ac
Δ = -102-4·12·3
Δ = -44
Delta is less than zero, so there is no solution for the equation