3(2d-4)=6(d-2)

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Solution for 3(2d-4)=6(d-2) equation: 



3(2d-4)=6(d-2)

We move all terms to the left:

3(2d-4)-(6(d-2))=0

We multiply parentheses

6d-(6(d-2))-12=0



We calculate terms in parentheses: -(6(d-2)), so:

6(d-2)

We multiply parentheses

6d-12

Back to the equation:

-(6d-12)



We get rid of parentheses

6d-6d+12-12=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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