3(2d-7)=2(4d+2)

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Solution for 3(2d-7)=2(4d+2) equation: 



3(2d-7)=2(4d+2)

We move all terms to the left:

3(2d-7)-(2(4d+2))=0

We multiply parentheses

6d-(2(4d+2))-21=0



We calculate terms in parentheses: -(2(4d+2)), so:

2(4d+2)

We multiply parentheses

8d+4

Back to the equation:

-(8d+4)



We get rid of parentheses

6d-8d-4-21=0

We add all the numbers together, and all the variables

-2d-25=0

We move all terms containing d to the left, all other terms to the right

-2d=25

d=25/-2

d=-12+1/2

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