3(2e-4)-e=2(14-2e)+e

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Solution for 3(2e-4)-e=2(14-2e)+e equation: 



3(2e-4)-e=2(14-2e)+e

We move all terms to the left:

3(2e-4)-e-(2(14-2e)+e)=0

We add all the numbers together, and all the variables

3(2e-4)-e-(2(-2e+14)+e)=0

We add all the numbers together, and all the variables

-1e+3(2e-4)-(2(-2e+14)+e)=0

We multiply parentheses

-1e+6e-(2(-2e+14)+e)-12=0



We calculate terms in parentheses: -(2(-2e+14)+e), so:

2(-2e+14)+e

We add all the numbers together, and all the variables

e+2(-2e+14)

We multiply parentheses

e-4e+28

We add all the numbers together, and all the variables

-3e+28

Back to the equation:

-(-3e+28)



We add all the numbers together, and all the variables

5e-(-3e+28)-12=0

We get rid of parentheses

5e+3e-28-12=0

We add all the numbers together, and all the variables

8e-40=0

We move all terms containing e to the left, all other terms to the right

8e=40

e=40/8

e=5

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