3(2f+1)+7f=55

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Solution for 3(2f+1)+7f=55 equation:


Simplifying
3(2f + 1) + 7f = 55

Reorder the terms:
3(1 + 2f) + 7f = 55
(1 * 3 + 2f * 3) + 7f = 55
(3 + 6f) + 7f = 55

Combine like terms: 6f + 7f = 13f
3 + 13f = 55

Solving
3 + 13f = 55

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 13f = 55 + -3

Combine like terms: 3 + -3 = 0
0 + 13f = 55 + -3
13f = 55 + -3

Combine like terms: 55 + -3 = 52
13f = 52

Divide each side by '13'.
f = 4

Simplifying
f = 4

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