3(2f+2)=6(2f+6)

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Solution for 3(2f+2)=6(2f+6) equation: 



3(2f+2)=6(2f+6)

We move all terms to the left:

3(2f+2)-(6(2f+6))=0

We multiply parentheses

6f-(6(2f+6))+6=0



We calculate terms in parentheses: -(6(2f+6)), so:

6(2f+6)

We multiply parentheses

12f+36

Back to the equation:

-(12f+36)



We get rid of parentheses

6f-12f-36+6=0

We add all the numbers together, and all the variables

-6f-30=0

We move all terms containing f to the left, all other terms to the right

-6f=30

f=30/-6

f=-5

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