3(2f+4)=-2f(3f-6)

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Solution for 3(2f+4)=-2f(3f-6) equation:



3(2f+4)=-2f(3f-6)
We move all terms to the left:
3(2f+4)-(-2f(3f-6))=0
We multiply parentheses
6f-(-2f(3f-6))+12=0
We calculate terms in parentheses: -(-2f(3f-6)), so:
-2f(3f-6)
We multiply parentheses
-6f^2+12f
Back to the equation:
-(-6f^2+12f)
We get rid of parentheses
6f^2-12f+6f+12=0
We add all the numbers together, and all the variables
6f^2-6f+12=0
a = 6; b = -6; c = +12;
Δ = b2-4ac
Δ = -62-4·6·12
Δ = -252
Delta is less than zero, so there is no solution for the equation

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