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3(2f+4)=2(3f-2)
We move all terms to the left:
3(2f+4)-(2(3f-2))=0
We multiply parentheses
6f-(2(3f-2))+12=0
We calculate terms in parentheses: -(2(3f-2)), so:We get rid of parentheses
2(3f-2)
We multiply parentheses
6f-4
Back to the equation:
-(6f-4)
6f-6f+4+12=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation
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