3(2f+4)=2(3f-6)=36

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Solution for 3(2f+4)=2(3f-6)=36 equation: 



3(2f+4)=2(3f-6)=36

We move all terms to the left:

3(2f+4)-(2(3f-6))=0

We multiply parentheses

6f-(2(3f-6))+12=0



We calculate terms in parentheses: -(2(3f-6)), so:

2(3f-6)

We multiply parentheses

6f-12

Back to the equation:

-(6f-12)



We get rid of parentheses

6f-6f+12+12=0

We add all the numbers together, and all the variables

24!=0

There is no solution for this equation

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