3(2f+5)=4(7-f)

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Solution for 3(2f+5)=4(7-f) equation:



3(2f+5)=4(7-f)
We move all terms to the left:
3(2f+5)-(4(7-f))=0
We add all the numbers together, and all the variables
3(2f+5)-(4(-1f+7))=0
We multiply parentheses
6f-(4(-1f+7))+15=0
We calculate terms in parentheses: -(4(-1f+7)), so:
4(-1f+7)
We multiply parentheses
-4f+28
Back to the equation:
-(-4f+28)
We get rid of parentheses
6f+4f-28+15=0
We add all the numbers together, and all the variables
10f-13=0
We move all terms containing f to the left, all other terms to the right
10f=13
f=13/10
f=1+3/10

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