3(2f+5)=5(f+1)

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Solution for 3(2f+5)=5(f+1) equation:


Simplifying
3(2f + 5) = 5(f + 1)

Reorder the terms:
3(5 + 2f) = 5(f + 1)
(5 * 3 + 2f * 3) = 5(f + 1)
(15 + 6f) = 5(f + 1)

Reorder the terms:
15 + 6f = 5(1 + f)
15 + 6f = (1 * 5 + f * 5)
15 + 6f = (5 + 5f)

Solving
15 + 6f = 5 + 5f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-5f' to each side of the equation.
15 + 6f + -5f = 5 + 5f + -5f

Combine like terms: 6f + -5f = 1f
15 + 1f = 5 + 5f + -5f

Combine like terms: 5f + -5f = 0
15 + 1f = 5 + 0
15 + 1f = 5

Add '-15' to each side of the equation.
15 + -15 + 1f = 5 + -15

Combine like terms: 15 + -15 = 0
0 + 1f = 5 + -15
1f = 5 + -15

Combine like terms: 5 + -15 = -10
1f = -10

Divide each side by '1'.
f = -10

Simplifying
f = -10

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