3(2f+f)=4(7-f)

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Solution for 3(2f+f)=4(7-f) equation: 



3(2f+f)=4(7-f)

We move all terms to the left:

3(2f+f)-(4(7-f))=0

We add all the numbers together, and all the variables

3(+3f)-(4(-1f+7))=0

We multiply parentheses

9f-(4(-1f+7))=0



We calculate terms in parentheses: -(4(-1f+7)), so:

4(-1f+7)

We multiply parentheses

-4f+28

Back to the equation:

-(-4f+28)



We get rid of parentheses

9f+4f-28=0

We add all the numbers together, and all the variables

13f-28=0

We move all terms containing f to the left, all other terms to the right

13f=28

f=28/13

f=2+2/13

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