3(2f-7)=12f-18

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Solution for 3(2f-7)=12f-18 equation: 



3(2f-7)=12f-18

We move all terms to the left:

3(2f-7)-(12f-18)=0

We multiply parentheses

6f-(12f-18)-21=0

We get rid of parentheses

6f-12f+18-21=0

We add all the numbers together, and all the variables

-6f-3=0

We move all terms containing f to the left, all other terms to the right

-6f=3

f=3/-6

f=-1/2

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