3(2g-5)-1=9-(4g+5)

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Solution for 3(2g-5)-1=9-(4g+5) equation: 



3(2g-5)-1=9-(4g+5)

We move all terms to the left:

3(2g-5)-1-(9-(4g+5))=0

We multiply parentheses

6g-(9-(4g+5))-15-1=0



We calculate terms in parentheses: -(9-(4g+5)), so:

9-(4g+5)

determiningTheFunctionDomain
-(4g+5)+9

We get rid of parentheses

-4g-5+9

We add all the numbers together, and all the variables

-4g+4

Back to the equation:

-(-4g+4)



We add all the numbers together, and all the variables

6g-(-4g+4)-16=0

We get rid of parentheses

6g+4g-4-16=0

We add all the numbers together, and all the variables

10g-20=0

We move all terms containing g to the left, all other terms to the right

10g=20

g=20/10

g=2

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