3(2h+2)-2(h+9)=2(h-9)-2

Solution for 3(2h+2)-2(h+9)=2(h-9)-2 equation:

3(2h+2)-2(h+9)=2(h-9)-2

We move all terms to the left:

3(2h+2)-2(h+9)-(2(h-9)-2)=0

We multiply parentheses

6h-2h-(2(h-9)-2)+6-18=0


We calculate terms in parentheses: -(2(h-9)-2), so:

2(h-9)-2

We multiply parentheses

2h-18-2

We add all the numbers together, and all the variables

2h-20

Back to the equation:

-(2h-20)


We add all the numbers together, and all the variables

4h-(2h-20)-12=0

We get rid of parentheses

4h-2h+20-12=0

We add all the numbers together, and all the variables

2h+8=0

We move all terms containing h to the left, all other terms to the right

2h=-8

h=-8/2

h=-4