3(2j+3)-2(j+2)=

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Solution for 3(2j+3)-2(j+2)= equation:


Simplifying
3(2j + 3) + -2(j + 2) = 0

Reorder the terms:
3(3 + 2j) + -2(j + 2) = 0
(3 * 3 + 2j * 3) + -2(j + 2) = 0
(9 + 6j) + -2(j + 2) = 0

Reorder the terms:
9 + 6j + -2(2 + j) = 0
9 + 6j + (2 * -2 + j * -2) = 0
9 + 6j + (-4 + -2j) = 0

Reorder the terms:
9 + -4 + 6j + -2j = 0

Combine like terms: 9 + -4 = 5
5 + 6j + -2j = 0

Combine like terms: 6j + -2j = 4j
5 + 4j = 0

Solving
5 + 4j = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 4j = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 4j = 0 + -5
4j = 0 + -5

Combine like terms: 0 + -5 = -5
4j = -5

Divide each side by '4'.
j = -1.25

Simplifying
j = -1.25

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