3(2j-5)=6(j-2)-3

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Solution for 3(2j-5)=6(j-2)-3 equation: 



3(2j-5)=6(j-2)-3

We move all terms to the left:

3(2j-5)-(6(j-2)-3)=0

We multiply parentheses

6j-(6(j-2)-3)-15=0



We calculate terms in parentheses: -(6(j-2)-3), so:

6(j-2)-3

We multiply parentheses

6j-12-3

We add all the numbers together, and all the variables

6j-15

Back to the equation:

-(6j-15)



We get rid of parentheses

6j-6j+15-15=0

We add all the numbers together, and all the variables

=0

j=0/1

j=0

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