3(2j/3-6)=32

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Solution for 3(2j/3-6)=32 equation: 



3(2j/3-6)=32

We move all terms to the left:

3(2j/3-6)-(32)=0

We multiply parentheses

6j-18-32=0

We add all the numbers together, and all the variables

6j-50=0

We move all terms containing j to the left, all other terms to the right

6j=50

j=50/6

j=8+1/3

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