3(2k)+5=2(2k+1)+1

Solution for 3(2k)+5=2(2k+1)+1 equation:

3(2k)+5=2(2k+1)+1

We move all terms to the left:

3(2k)+5-(2(2k+1)+1)=0


We calculate terms in parentheses: -(2(2k+1)+1), so:

2(2k+1)+1

We multiply parentheses

4k+2+1

We add all the numbers together, and all the variables

4k+3

Back to the equation:

-(4k+3)


We get rid of parentheses

32k-4k-3+5=0

We add all the numbers together, and all the variables

28k+2=0

We move all terms containing k to the left, all other terms to the right

28k=-2

k=-2/28

k=-1/14