3(2k+1)=4(k+2)-1

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Solution for 3(2k+1)=4(k+2)-1 equation: 


Simplifying
3(2k + 1) = 4(k + 2) + -1

Reorder the terms:
3(1 + 2k) = 4(k + 2) + -1
(1 * 3 + 2k * 3) = 4(k + 2) + -1
(3 + 6k) = 4(k + 2) + -1

Reorder the terms:
3 + 6k = 4(2 + k) + -1
3 + 6k = (2 * 4 + k * 4) + -1
3 + 6k = (8 + 4k) + -1

Reorder the terms:
3 + 6k = 8 + -1 + 4k

Combine like terms: 8 + -1 = 7
3 + 6k = 7 + 4k

Solving
3 + 6k = 7 + 4k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-4k' to each side of the equation.
3 + 6k + -4k = 7 + 4k + -4k

Combine like terms: 6k + -4k = 2k
3 + 2k = 7 + 4k + -4k

Combine like terms: 4k + -4k = 0
3 + 2k = 7 + 0
3 + 2k = 7

Add '-3' to each side of the equation.
3 + -3 + 2k = 7 + -3

Combine like terms: 3 + -3 = 0
0 + 2k = 7 + -3
2k = 7 + -3

Combine like terms: 7 + -3 = 4
2k = 4

Divide each side by '2'.
k = 2

Simplifying
k = 2

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