3(2k+2)=36

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Solution for 3(2k+2)=36 equation: 



3(2k+2)=36

We move all terms to the left:

3(2k+2)-(36)=0

We multiply parentheses

6k+6-36=0

We add all the numbers together, and all the variables

6k-30=0

We move all terms containing k to the left, all other terms to the right

6k=30

k=30/6

k=5

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