3(2k+3)=3k+27

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Solution for 3(2k+3)=3k+27 equation: 



3(2k+3)=3k+27

We move all terms to the left:

3(2k+3)-(3k+27)=0

We multiply parentheses

6k-(3k+27)+9=0

We get rid of parentheses

6k-3k-27+9=0

We add all the numbers together, and all the variables

3k-18=0

We move all terms containing k to the left, all other terms to the right

3k=18

k=18/3

k=6

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